Consider the oxidation of sodium metal to sodium oxide described by the balanced equation: 4 Na + O2 → 2 Na2O. What is the theoretical

Question

Consider the oxidation of sodium metal to sodium oxide described by the balanced equation:
4 Na + O2 → 2 Na2O. What is the theoretical yield of Na2O in grams from 9.0 mol of O2?

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Thiên Ân 4 years 2021-08-24T12:01:55+00:00 1 Answers 88 views 0

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  1. thienthi
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    2021-08-24T12:03:30+00:00
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    Answer:

    1116 g.

    Explanation:

    The balanced equation for the reaction is given below:

    4Na + O₂ —> 2Na₂O

    From the balanced equation above,

    1 mole of O₂ reacted to produce 2 moles of Na₂O.

    Next, we shall determine the theoretical yield of Na₂O. This can be obtained as follow:

    From the balanced equation above,

    1 mole of O₂ reacted to produce 2 moles of Na₂O.

    Therefore, 9 moles of O₂ will react to produce = 9 × 2 = 18 moles of Na₂O.

    Finally, we shall determine the mass in 18 moles of Na₂O. This can be obtained as follow:

    Mole of Na₂O = 18 moles

    Molar mass of Na₂O = (23×2) + 16

    = 46 + 16

    = 62 g/mol

    Mass of Na₂O =?

    Mass = mole × molar mass

    Mass of Na₂O = 18 × 62

    Mass of Na₂O = 1116 g

    Thus, the theoretical yield of Na₂O is 1116 g.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )