Calculate the total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees

Question

Calculate the total energy, in kilojoules, that is needed to turn a 46 g block
of ice at -25 degrees C into water vapor at 100 degrees C.

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Nick 4 years 2021-07-24T13:07:43+00:00 1 Answers 13 views 0

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  1. Cherry
    0
    2021-07-24T13:09:11+00:00
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    Answer: The total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees C is 11.787 kJ.

    Explanation:

    Given: Mass = 46 g

    Initial temperature = -25^{o}C

    Final temperature = 100^{o}C

    Specific heat capacity of ice = 2.05 J/g^{o}C

    Formula used to calculate the energy is as follows.

    q = m \times C \times (T_{2} - T_{1})

    where,

    q = heat energy

    m = mass

    C = specific heat capacity

    T_{1} = initial temperature

    T_{2} = final temperature

    Substitute the values into above formula as follows.

    q = m \times C \times (T_{2} - T_{1})\\= 46 g \times 2.05 J/g^{o}C \times (100 - (-25))^{o}C\\= 11787.5 J (1 J = 0.001 kJ)\\= 11.787 kJ

    Thus, we can conclude that the total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees C is 11.787 kJ.

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