Calculate the total amount of energy required in calories to convert 50.0 g of ice at 0.00 degrees Celsius to steam at 100. degrees Celsius.

Question

Calculate the total amount of energy required in calories to convert 50.0 g of ice at 0.00 degrees Celsius to steam at 100. degrees Celsius.
Specific heat capacity of water is 1.00 cal/g OC
Hfusion = 80 cal/g OC and Hvap = 540 cal/g OC
Write the complete equation you will use. 1 point
Substitute the values in the equation in step 1. 1 point
Report the math answer with 3 sig figs and the correct unit. 1 point

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Nguyệt Ánh 4 years 2021-07-22T22:32:59+00:00 1 Answers 20 views 0

Answers ( )

  1. ngockhue
    0
    2021-07-22T22:34:06+00:00
    Reply

    Answer:

    HFusion*mass + Spec.Heat*mass*ΔT + HVap*mass

    80cal/g*50.0g + 1.00cal/g°C*50.0g*(100°C-0°C) + 540cal/g*50g

    3.60×10⁵cal

    Explanation:

    Using the HFusion we can find the heat needed to convert the ice to liquid water.

    With specific heat capacity we can find the heat needed to increase the temperature of water from 0 to 100°C.

    With HVap we can find the heat to convert the liquid water into steam.

    The equations are:

    HFusion*mass + Spec.Heat*mass*ΔT + HVap*mass

    Computing the values:

    80cal/g*50.0g + 1.00cal/g°C*50.0g*(100°C-0°C) + 540cal/g*50g

    36000cal =

    3.60×10⁵cal

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