Calculate the molality of a solution that contains 51.2 g of naphthalene, C10H8, in 500 mL of carbon tetrachloride. The density of CCl4 is 1

Question

Calculate the molality of a solution that contains 51.2 g of naphthalene, C10H8, in 500 mL of carbon tetrachloride. The density of CCl4 is 1.60 g/mL.

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Adela 4 years 2021-07-19T02:04:39+00:00 1 Answers 28 views 0

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  1. Dulcie
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    2021-07-19T02:06:05+00:00
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    Answer: The molality of naphthalene solution is 0.499 m

    Explanation:

    Density is defined as the ratio of mass and volume of a substance.

    \text{Density}=\frac{\text{Mass}}{\text{Volume}} ……(1)

    Given values:

    Volume of carbon tetrachloride = 500 mL

    Density of carbon tetrachloride = 1.60 g/mL

    Putting values in equation 1, we get:

    \text{Mass of carbon tetrachloride}=(1.60g/mL\times 500mL)=800g

    Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molarity:

    \text{Molality of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent (in g)}} …..(2)

    Given values:

    Given mass of naphthalene = 51.2 g

    Molar mass of naphthalene = 128.17 g/mol

    Mass of solvent = 800 g

    Putting values in equation 2, we get:

    \text{Molality of naphthalene}=\frac{51.2\times 1000}{128.17\times 800}\\\\\text{Molality of naphthalene}=0.499m

    Hence, the molality of naphthalene solution is 0.499 m

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