c) An aluminum tea kettle with mass 1.10 kg containing 1.80 kg of water is placed on a stove. If no heat is lost to the surroundings, how mu

Question

c) An aluminum tea kettle with mass 1.10 kg containing 1.80 kg of water is placed on a stove. If no heat is lost to the surroundings, how much heat must be added to raise the temperature from 20o C to 95o C

in progress 0
Minh Khuê 5 years 2021-07-15T15:47:38+00:00 1 Answers 1098 views 0

Answers ( )

  1. thienthanh
    0
    2021-07-15T15:49:35+00:00
    Reply

    Answer:

    Q = 640425 J = 640.425 KJ

    Explanation:

    From the law of conservation of energy:

    Heat Addition = Heat Gain of Water + Heat Gain of Aluminum Kettle

    Q = m_wC_w\Delta T_w + m_aC_a\Delta T_a

    where,

    Q = Heat addition required = ?

    m_w = mass of water =1.8 kg

    m_a = mass of aluminum kettle = 1.1 kg

    C_w = specific heat capacity of water = = 4200 J/kg.°C

    C_a  = specific heat capacity of aluminum kettle = = 890 J/kg.°C

    \Delta T_w = \Delta T_a = change in temperature of water and kettle = 95°C – 20°C = 75°C

    Therefore,

    Q = (1.8\ kg)(4200\ J/kg.^oC)(75^oC)+(1.1\ kg)(890\ J/kg.^oC)(75^oC)\\

    Q = 567000 J + 73425 J

    Q = 640425 J = 640.425 KJ

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )