Bulb ܣ is rated for 20W at 12V. Bulb ܤ is rated for 20W at 120V. The two bulbs are mistakenly mixed up so that bulb ܣ is connected to a 120V

Question

Bulb ܣ is rated for 20W at 12V. Bulb ܤ is rated for 20W at 120V. The two bulbs are mistakenly mixed up so that bulb ܣ is connected to a 120V line and bulb ܤ is connected to a 12V line. a. Determine the power dissipated by Bulb ܣ while connected to the 120Vline. b. Determine the power dissipated by Bulb ܤ while connected to the 12Vline. c. Which bulb, if any, is more likely to burn out and why?

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Amity 4 years 2021-09-02T13:14:57+00:00 1 Answers 11 views 0

Answers ( )

  1. Giakhanh
    0
    2021-09-02T13:16:35+00:00
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    Answer:

    a. 2000W

    b.0.2W

    c. Bulb 1

    Explanation:

    Data given:

    bulb 1 rating =20w,12v

    bulb 2 rating =20w,120v.

    we calculate the resistance for each bulb

    bulb 1: R=\frac{V^2}{P}\\ bulb 1: R=\frac{12^2}{20}\\ R=7.2 ohms

    for bulb 2

    bulb 2: R=\frac{V^2}{P}\\ bulb 2: R=\frac{120^2}{20}\\ R=720 ohms

    when miss connection occur we need to calculate the dissipated power from wash bulb

    a. for bulb 1 with R=7.2ohms and V=120v,

    the power is calculated as

    P=\frac{v^2}{R}\\ P=\frac{120^2}{7.2}\\ P=2000W

    b. for bulb 2 with R=720 ohms and V=12v,

    the power is calculated as

    P=\frac{v^2}{R}\\ P=\frac{12^2}{720}\\ P=0.2W\\

    c. Bulb 1 is more likely to burn out because it is operating above the rated power.

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