As a protest against the umpire’s calls, a baseball pitcher throws a ball straight up into the air at a speed of 19.0 m/s. In the process, h

Question

As a protest against the umpire’s calls, a baseball pitcher throws a ball straight up into the air at a speed of 19.0 m/s. In the process, he moves his hand through a distance of 1.10 m. If the ball has a mass of 0.150 kg, find the force he exerts on the ball to give it this upward speed.

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Vân Khánh 4 years 2021-08-28T23:51:31+00:00 1 Answers 15 views 0

Answers ( )

  1. Gerda
    0
    2021-08-28T23:52:43+00:00
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    Answer:

    F_{player}=26.1N

    Explanation:

    Given data

    Initial speed vi=0 m/s

    Final speed vf=19.0 m/s

    Δy=1.10 m

    Mass of ball m=0.150 kg

    To find

    Force

    Solution

    First we need to find acceleration of the ball.So we can apply:

    vf²=vi²+2aΔy

    vf²=0+2aΔy

    a=\frac{(19.0m/s)^2}{2*1.10m}\\ a=164.1m/s^2

    Because we get the acceleration of the ball.We can now find the force the players exerts on the ball by using Newtons second law

    ∑F=F.player -mg=ma

    F_{player}-mg=ma\\F_{player}=mg+ma\\F_{player}=m[g+a]\\F_{player}=0.150kg[9.81+164.1]\\F_{player}=26.1N

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