An open-pipe resonator has a length of 2.39 m. Calculate the frequency of its third harmonic if the speed of sound is 343 m/s. 80 Hz

Question

An open-pipe resonator has a length of 2.39 m. Calculate the frequency of its third harmonic if the speed of sound is 343 m/s.
80 Hz
115.7 Hz
215.27 Hz
100.1 Hz

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Thiên Thanh 4 years 2021-09-02T00:36:10+00:00 1 Answers 13 views 0

Answers ( )

  1. kiet
    0
    2021-09-02T00:38:06+00:00
    Reply

    Answer:

    f = 215.27 Hz

    Explanation:

    We have,

    An open-pipe resonator has a length of 2.39 m.

    It is required to find the frequency of its third harmonic if the speed of sound is 343 m/s.

    For third harmonic, its length is equal to, l=\dfrac{3\lambda}{2}

    So,

    \dfrac{3v}{2f}=2.39

    f is frequency in its third harmonics

    f=\dfrac{3v}{2\times 2.39}\\\\f=\dfrac{3\times 343}{2\times 2.39}\\\\f=215.27\ Hz

    So, the frequency of its third harmonic is 215.27 Hz.

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