An object is constrained by a cord to move in a circular path of radius 1-m on a frictionless, horizontal surface. The cord will break if th

Question

An object is constrained by a cord to move in a circular path of radius 1-m on a frictionless, horizontal surface. The cord will break if the tension exceeds 26.9-N. The maximum kinetic energy that this object can have is _____ J. Round your answer to the nearest whole number.

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Gerda 4 years 2021-09-05T08:24:13+00:00 1 Answers 21 views 0

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  1. ngockhue
    0
    2021-09-05T08:25:26+00:00
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    Answer:

    Explanation:

    Let m be the mass of the object and v be the maximum velocity . The tension will provide centripetal force for the circular motion .

    T = mv² / R where R is radius of circular path . T is tension .

    putting the values given in the equation above

    26.9 = m v² / 1

    m v² = 26.9

    kinetic enrgy = 1/2 m v²

    = 26.9 / 2

    = 13.45 J

    13 J .

    Maximum kinetic energy = 13 J .

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