An initially unpolarized beam of light, intensity Io , is propagating into the plane of the paper. The light travels through 4 linear polari

Question

An initially unpolarized beam of light, intensity Io , is propagating into the plane of the paper. The light travels through 4 linear polarizers. As measured counterclockwise from due East the angles of the polarizers are: 0 degrees, 45 degrees, 45 degrees, 90 degrees. If the final intensity of the light is 0.125Io what order must the polarizers be placed in (more than one right answer)?

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Thiên Thanh 4 years 2021-08-05T08:40:20+00:00 1 Answers 8 views 0

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  1. Orla
    0
    2021-08-05T08:41:58+00:00
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    Answer:

    Answer is given below.

    Explanation:

    1.

    Solution:

    Let the polarizers be P_{1} , P_{2} , P_{3} and P_{4} inclined at 0^{o} , 45^{o} ,45^{o}& 90^{o} counterclockwise from East..

    (A)Consider the arrangement P_{1} P_{2}P_{3}P_{4}.

    By Malu’s Law,

    I = lo cos

    When the unpolarized light passes through P_{1} , the intensity of light transmitted is equal to half of incident light.

    Thus, the intensity of light passing through P_{1} is

    I_{1}=\frac{1}{2}I_{O}

     P_{1} and P_{2} are inclined at 45^{0} . The intensity of light transmitted through P_{2} is

    01 = 7505 0 = 21

    P_{2} and  P_{3} are inclined at 0^{0} to each other. The intensity of light transmitted through P_{3} is

     13 = -lo cos?o= =10

     P_{3} and P_{4} are inclined at 45^{0} to each other. The intensity of light transmitted through P_{4} is

     14 = -lo cos? 45 = -10=0.12510

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