An inductor is hooked up to an AC voltage source. The voltage source has EMF V0 and frequency f. The current amplitude in the inductor is I0

Question

An inductor is hooked up to an AC voltage source. The voltage source has EMF V0 and frequency f. The current amplitude in the inductor is I0.
Part A
What is the reactance XL of the inductor?
Express your answer in terms of V0 and I0.
Part B
What is the inductance L of the inductor?
Express your answer in terms of V0, f, and I0.

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Latifah 3 years 2021-08-11T04:11:21+00:00 1 Answers 79 views 0

Answers ( )

  1. thaiduong
    1
    2021-08-11T04:12:49+00:00
    Reply

    Answer:

    a. The reactance of the inductor is XL = V₀/I₀

    b. The inductance of the inductor is L = V₀/2πfI₀

    Explanation:

    PART A

    Since the voltage across the inductor V₀ = I₀XL where V₀ = e.m.f of voltage source, I₀ = current amplitude and XL = reactance of the inductor,

    XL = V₀/I₀

    So, the reactance of the inductor is XL = V₀/I₀

    PART B

    The inductance of the inductor is gotten from XL = 2πfL where f = frequency of voltage source and L = inductance of inductor

    Since XL = V₀/I₀ = 2πfL

    V₀/I₀ = 2πfL

    L = V₀/2πfI₀

    So the inductance of the inductor is L = V₀/2πfI₀

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