an ant crawls at a rate of 2 1/6 feet per minute at this rate how long does it take to end to call a distance of 5 1/5 ft enter your answer

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an ant crawls at a rate of 2 1/6 feet per minute at this rate how long does it take to end to call a distance of 5 1/5 ft enter your answer as a mixed number in simplest form ​

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Kiệt Gia 4 years 2021-07-18T15:59:19+00:00 1 Answers 18 views 0

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  1. quangkhai
    0
    2021-07-18T16:00:40+00:00
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    Step-by-step explanation:

    Given :Ant crawls at the rate 2\frac{1}{6}

    6

    1

    ft /min

    =\frac{12+1}{6}

    6

    12+1

    ft

    =\frac{13}{6}

    6

    13

    ft

    Distance: 5\frac{1}{5}

    5

    1

    ft

    =\frac{25+1}{5}

    5

    25+1

    ft

    =\frac{26}{5}

    5

    26

    ft

    Time taken =\frac{Distance}{Speed}

    Speed

    Distance

    =\frac{26/5}{13/6}

    13/6

    26/5

    \frac{26*6}{5*13}

    5∗13

    26∗6

    Dividing numerator and denominator by 13

    =\frac{12}{5}

    5

    12

    =2\frac{2}{5}

    5

    2

    min

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )