An alpha particle (charge +2e) and an electron move in opposite directions from the same point, each with the speed of 2.80×10^5 m/s . Find

Question

An alpha particle (charge +2e) and an electron move in opposite directions from the same point, each with the speed of 2.80×10^5 m/s . Find the total magnetic field these charges produce at point P, which is 8.25 nm from each charge. μ0=4πx10^-7 H/m, 1nm= 10^-9 m.

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Phúc Điền 4 years 2021-08-17T14:22:33+00:00 1 Answers 8 views 0

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  1. binhan
    0
    2021-08-17T14:23:47+00:00
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    Answer:

    Explanation:

    Magnetic field due to moving charge =

    B=\frac{\mu_0}{4\pi} \times \frac{qv}{r^2}

    q is charge moving with velocity v and r is distance from point at which field is calculated .

    For alpha particle

    B_1=\frac{\mu_0}{4\pi} \times \frac{2\times 1.6\times10^{-19}\times 2.8\times 10^5}{(8.25\times 10^{-9})^2}

    = 0.1316 x 10⁻³ T

    For electron

    B_2=\frac{\mu_0}{4\pi} \times \frac{ 1.6\times10^{-19}\times 2.8\times 10^5}{(8.25\times 10^{-9})^2}

    = .0658 x 10⁻³ T .

    Both these magnetic field will be same in direction because direction of equivalent current is same for both the particles .

    Hence

    Total magnetic field

    = B₁ + B₂ = .1974 x 10⁻³

    = 1.974 x 10⁻⁴ T .

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