Aluminum reacts with chlorine gas to produce aluminum chloride crystals. How many grams of aluminum chloride will be produced if the reactio

Question

Aluminum reacts with chlorine gas to produce aluminum chloride crystals. How many grams of aluminum chloride will be produced if the reaction begins with 135.0g of Al and 475.0 g chlorine gas.

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Xavia 4 years 2021-08-09T06:48:18+00:00 1 Answers 22 views 0

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  1. Nick
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    2021-08-09T06:50:01+00:00
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    Answer:

    596 g of AlCl₃

    Explanation:

    The reaction is:

    2Al + 3Cl₂  →  2AlCl₃

    Firstly we need to determine the limiting reactant and we need to determine the moles of each

    135 g . 1 mol / 26.98 g = 5 moles of Al

    475 g . 1mol / 70.9 g = 6.7 moles of chlorine

    Ratio in the reaction is 3:2

    3 moles of chlorine gas need 2 moles of Al to react

    Then, our 6.7 moles of gas might react to (6.7 . 2 ) /3 = 4.47 moles of Al

    We have 5 moles of Al and we need 4.47 moles, so this is the excess reactant. In conclussion, Cl₂ is the limiting.

    2 moles of Al react to 3 moles of gas

    Our 5 moles of Al may react to (5 . 3 )/2 = 7.5 moles of gas

    It’s ok because we only have 6.7 moles, and there is not enough gas.

    Now we calculate the product’s mass

    3 moles of gas can produce 2 moles of salt

    Then, our 6.7 moles of gas will produce (6.7 . 2) /3 = 4.47 moles

    We convert moles to mass: 4.47 mol . 133.33 g/mol = 596 g of AlCl₃

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