After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 48.0 cm . The explorer finds that the pendulu

Question

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 48.0 cm . The explorer finds that the pendulum completes 93.0 full swing cycles in a time of 141 s.

Required:
What is the value of g on this planet?

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Thiên Ân 3 years 2021-08-14T19:59:18+00:00 1 Answers 10 views 0

Answers ( )

  1. giabao
    0
    2021-08-14T20:01:06+00:00
    Reply

    Answer:

    8.24 m/s²

    Explanation:

    Applying,

    T = 2π√(L/g)……………….. Equation 1

    Where T = period of the pendulum, L = Length of the pendulum, g = acceleration due to gravity of the planet, π = pi

    From the question, we were asked to  find the value of g,

    There we make g the subject of the equation

    g = 4π²L/T²………………… Equation 2

    Given: L= 48 cm = 0.48 m, T = (141/93) s = 1.516 s

    Constant: π = 3.14

    Substitute these values into equation 2

    g = 4(3.14²)(0.48)/(1.516²)

    g = 18.93/2.298

    g = 8.24 m/s².

    Hence the acceleration of the planet is 8.24 m/s²

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