A very bouncy ball is dropped from a height of 2.47 m to an asphalt playground surface and the height of its 4 th bounce is measured to be 1

Question

A very bouncy ball is dropped from a height of 2.47 m to an asphalt playground surface and the height of its 4 th bounce is measured to be 1.71 m. Find the coefficient of restitution of the ball for a collision with asphalt.

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Sapo 4 years 2021-08-17T15:03:04+00:00 1 Answers 25 views 0

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    2021-08-17T15:04:06+00:00

    Answer:

    0.912

    Explanation:

    Given that

    Height of bouncing of the ball, h = 1.71 m

    Number of times the ball bounced, n = 4 times

    Height from which the ball was dropped, H = 2.47

    First, let’s start by defining what coefficient of restitution means

    Coefficient of Restitution, CoR is the “ratio of the final to initial relative velocity between two objects after they collide. It normally ranges from 0 to 1 where 1 would be a perfectly elastic collision.”

    It is mathematically represented as

    CoR = (velocity after collision) / (velocity before collision)

    1.71 = 2.47 * c^4, where c = CoR

    1.71/2.47 = c^4

    c^4 = 0.6923

    c = 4th root of 0.6923

    c = 0.912

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