A uniform electric field is created by two parallel plates separated by a distance of 0.04 m. What is the magnitude of the electric field es

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A uniform electric field is created by two parallel plates separated by a distance of 0.04 m. What is the magnitude of the electric field established between the plates

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Euphemia 4 years 2021-08-14T18:53:50+00:00 1 Answers 481 views 1

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  1. hongcuc2
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    2021-08-14T18:55:16+00:00
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    Complete question:

    A uniform electric field is created by two parallel plates separated by a

    distance of 0.04 m. What is the magnitude of the electric field established

    between the plates if the potential of the first plate is +40V and the second

    one is -40V?

    Answer:

    The magnitude of the electric field established between the plates is 2,000 V/m

    Explanation:

    Given;

    distance between two parallel plates, d = 0.04 m

    potential between first and second plate, = +40V and -40V respectively

    The magnitude of the electric field established between the plates is calculated as;

    E = ΔV / d

    where;

    ΔV is change in potential between two parallel plates;

    d is the distance between the plates

    ΔV = V₁ -V₂

    ΔV = 40 – (-40)

    ΔV = 40 + 40

    ΔV = 80 V

    E = ΔV / d

    E = 80 / 0.04

    E = 2,000 V/m

    Therefore, the magnitude of the electric field established between the plates is 2,000 V/m

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )