A traveler pulls on a suitcase strap at an angle 36° above the horizontal. If 908 J of work are done by the strap while moving the suitcase

Question

A traveler pulls on a suitcase strap at an angle 36° above the horizontal. If 908 J of work are done by the strap while moving the suitcase a horizontal distance of 15 m, what is the tension in the strap?

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Thiên Ân 4 years 2021-09-05T12:27:39+00:00 1 Answers 557 views 0

Answers ( )

  1. Helga
    0
    2021-09-05T12:29:02+00:00
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    Answer:

    T = 74.8 N

    Explanation:

    Given:

    – The angle with the horizontal θ = 36°

    – The tension in the strap T

    – The amount of work done W = 908 J

    – The distance travelled by the suitcase s = 15 m

    Find:

    what is the tension in the strap?

    Solution:

    – From definition we have that the work-done by a force F is given by the dot product of the force vector and the displacement vector as expressed below:

                                            W = F.s

    –  The scalar form of the work done includes the component of force F along the direction of displacement as follows:

                                           W = F*s*cos(θ)

    – Now we can calculate the Tension force T from the given data as follows:

                                           W = T*s*cos(θ)

                                           T = W / (s*cos(θ))

                                           T = 908 / (15*cos(36))

                                          T = 74.8 N

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