“A thin film with an index of refraction of 1.50 is placed in one of the beams of a Michelson interferometer. If this causes a shift of 8 br

Question

“A thin film with an index of refraction of 1.50 is placed in one of the beams of a Michelson interferometer. If this causes a shift of 8 bright fringes in the pattern produced by light of wavelength 540 nm, what is the thickness of the film?”

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Ngọc Khuê 4 years 2021-08-10T08:51:31+00:00 1 Answers 11 views 0

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  1. thugiang
    0
    2021-08-10T08:52:31+00:00
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    Answer:

    The film thickness is 4.32 * 10^-6 m

    Explanation:

    Here in this question, we are interested in calculating the thickness of the film.

    Mathematically;

    The number of fringes shifted when we insert a film of refractive index n and thickness L in the Michelson Interferometer is given as;

    ΔN = (2L/λ) (n-1)

    where λ is the wavelength of the light used

    Let’s make L the subject of the formula

    (λ * ΔN)/2(n-1) = L

    From the question ΔN = 8 , λ = 540 nm, n = 1.5

    Plugging these values, we have

    L = ((540 * 10^-9 * 8)/2(1.5-1) = (4320 * 10^-9)/1 = 4.32 * 10^-6 m

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