A student is titrating 50ml of 2.5M HI with 1.23M NaOH. How many milliliters of base are added to reach the equivalence point?

Question

A student is titrating 50ml of 2.5M HI with 1.23M NaOH. How many milliliters of base are added to reach the
equivalence point?

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Vân Khánh 4 years 2021-08-03T20:19:06+00:00 1 Answers 12 views 0

Answers ( )

  1. Nem
    0
    2021-08-03T20:20:06+00:00
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    Answer:

    101.6ml

    Explanation:

    Using the formula;

    CaVa = CbVb

    Where;

    Ca = concentration of acid (M)

    Cb = concentration of base (M)

    Va = volume of acid (ml)

    Vb = volume of base (ml)

    Based on the information as follows:

    Ca = 2.5M

    Cb = 1.23M

    Va = 50ml

    Vb = ?

    Using CaVa = CbVb

    2.5 × 50 = 1.23 × Vb

    125 = 1.23Vb

    Vb = 125/1.23

    Vb = 101.6ml

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