A spring stretches from 10cm to 22cm when a force of 4n is applied, if it obeys Hooke’s law,its total length in cm when a force of 6N is app

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A spring stretches from 10cm to 22cm when a force of 4n is applied, if it obeys Hooke’s law,its total length in cm when a force of 6N is applied is?

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Euphemia 5 years 2021-07-25T02:26:30+00:00 1 Answers 202 views 0

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  1. Acacia
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    2021-07-25T02:27:34+00:00
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    Answer:

    Explanation:

    Hooke’s Law is a linear representation that, in equation form, looks like this:

    F = -kΔx where F is force, k is the spring constant, and Δx is the displacement of the spring when a Force is applied to it in the form of a mass hanging on the end of it. We need to use the equation to solve for the spring constant, k. Doing this by filling in the values we were given:

    4 = -k(-12) the 12 is negative because the mass hangs below the point of equilibrium. This gives us that

    k = 1/3. Now we’ll use that in the next equation where we need to solve for displacement:

    6 = -1/3(Δx) and

    Δx = -18 cm

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