A series combination of 12 Ω and 3 Ω is connected in parallel with another series combination of 6 Ω and 3 Ω. If a potential difference of 4

Question

A series combination of 12 Ω and 3 Ω is connected in parallel with another series combination of 6 Ω and 3 Ω. If a potential difference of 4 V is applied across it find the i) current drawn from the battery ii) current through 12 Ω resistor (iii)potential difference across 6 Ω resistor?

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Mộc Miên 4 years 2021-08-12T16:50:56+00:00 1 Answers 11 views 0

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  1. trucchi
    0
    2021-08-12T16:52:22+00:00
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    Answer:

    Explanation:

    Resultant of 12 and 3 ohm in series = 15 ohm

    Resultant of 6 and 3 ohm = 9 ohm

    Total resultant resistance of circuit = 15 x 9 / (15 + 9)

    = 5.625 ohm

    current drawn from battery = 4 / 5.625

    = .711 A

    ii )current through 12 ohm = 4 / (12 + 3 )   , because potential  diff over 12 and 6 ohm will be 4 V .

    current through 12 ohm = .267 A

    iii )

    current through 6 ohm

    = .711 – .267

    = .444 A

    potential difference

    = .444 x 6

    = 2.664 V .

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