A screen is separated from a double-slit source by a distance L. When light of wavelength 563 nm is incident on the double slit, the separat

Question

A screen is separated from a double-slit source by a distance L. When light of wavelength 563 nm is incident on the double slit, the separation distance between adjacent bright fringes on the screen is 0.0290 mm. When instead, 500 nm light is used, what is the separation distance (in mm) between adjacent bright fringes

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Thiên Ân 4 years 2021-08-10T09:06:39+00:00 1 Answers 11 views 0

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  1. giabao
    0
    2021-08-10T09:07:43+00:00
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    Answer:

    β 2 = 0.02575 mm

    Explanation:

    given data

    wavelength = 563 nm

    separation distance between adjacent bright fringes =  0.0290 mm

    wavelength = 500 nm

    solution

    we get here separation distance between adjacent bright fringes that is express as

    β = \frac{\lambda D }{d}    …………………………….1

    here D is distance from plane of slit to screen

    and d is slit sepation that is constant

    so

    \frac{\beta 1}{\beta 2} = \frac{\lambda 1}{\lambda 2}  

    β 2 = \frac{500}{563} \times 0.0290  

    β 2 = 0.02575 mm

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