A satellite m-500 kg orbits the earth at a distance d 215 km, above the surface of the planet. The radius of the earth is re 6.38 x 106 m an

Question

A satellite m-500 kg orbits the earth at a distance d 215 km, above the surface of the planet. The radius of the earth is re 6.38 x 106 m and the gravitational constant G-6.67 x 10-11 N m/kg2 and the Earth’s mass is me-5.98 x 1024 kg. ▲ What is the speed of the satellite in ms?

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Ngọc Diệp 5 years 2021-08-31T01:45:24+00:00 1 Answers 153 views 0

Answers ( )

  1. thienthi
    0
    2021-08-31T01:46:53+00:00
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    Answer:

    7.78 * 10³ m/s

    Explanation:

    Orbital velocity is given as:

    v = √(GM/R)

    G = 6.67 * 10^(-11) Nm/kg²

    M = 5.98 * 10^(24) kg

    R = radius of earth + distance of the satellite from the surface of the earth

    R = 2.15 * 10^(5) + 6.38 * 10^(6)

    R = 6.595 * 10^(6) m

    v = √([6.67 * 10^(-11) * 5.98 * 10^(24)] / 6.595 * 10^(6))

    v = √(6.048 * 10^7)

    v = 7.78 * 10³ m/s

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