A sample of oxygen is subjected to an absolute pressure of 2.4 atm. If the specific internal energy of the sample at 310 K is 5700 J/mol rel

Question

A sample of oxygen is subjected to an absolute pressure of 2.4 atm. If the specific internal energy of the sample at 310 K is 5700 J/mol relative to a known reference state, what is the specific enthalpy of the oxygen relative to that same reference state?

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Thu Nguyệt 3 years 2021-07-25T19:31:07+00:00 1 Answers 6 views 0

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    2021-07-25T19:32:27+00:00

    Answer:

    The required specific enthalpy for oxygen = 8277.34 J/mol

    Explanation:

    Given that :

    Pressure = 2.4 atm

    Temperature = 310 K

    specific internal energy U = 5700 J/mol

    To find the specific enthalpy using the formula:

    H = U + PV

    where;

    H is known as the specific enthalpy

    Recall that from ideal gas equation

    PV = nRT

    For specific enthalpy, it is constant that n = 1

    Thus;

    PV = RT

    replacing that into the equation (H = U + PV), we have:

    here;

    R = 8.314 J/mol K (constant)

    H = U + RT

    H = 5700 J/mol +( 8.314 J/mol K × 310 K)

    H = 5700 J/mol + ( 2577.34 J/mol)

    H = 8277.34 J/mol

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