A ray of light hits the surface between air and an unknown material at an angle A of 41.1°. It travels through the unknown material at an an

Question

A ray of light hits the surface between air and an unknown material at an angle A of 41.1°. It travels through the unknown material at an angle B of 27.7° relative to the vertical. What is the index of refraction of the material?

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Ben Gia 4 years 2021-07-20T03:25:28+00:00 1 Answers 13 views 0

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  1. Dau
    0
    2021-07-20T03:26:44+00:00
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    Answer:

    Refractive index of second material will be 1.41

    Explanation:

    It is given refractive index of first material, that is air n_1=1

    Angle of incidence = 41.1°

    Angle of refraction from second material = 27.7°

    We have to find the refractive index of second material.

    Now from Snell’s law n_1sini=n_2sinr

    1\times sin41.1=n_2\times sin27.7

    n_2=1.41

    So refractive index of second material will be equal to 1.4

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