A proton traveling to the right along the x-axis enters a region where there is a mag-netic field of magnitude 1.9 T directed upwardalong th

Question

A proton traveling to the right along the x-axis enters a region where there is a mag-netic field of magnitude 1.9 T directed upwardalong they-axis.The charge on a proton is 1.60×10−19C.If the proton experiences a force of 0.64×10−12N, find its speed.Answer in units of m/s.

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Thanh Hà 4 years 2021-08-16T10:27:08+00:00 1 Answers 15 views 0

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    2021-08-16T10:28:11+00:00

    Answer:

    Speed of the proton is given as

    v = 2.1 \times 10^6 m/s

    Explanation:

    As we know that force on moving charge is given as

    F = q(v\times B)

    here we know that charge is moving perpendicular to the field

    So we will have

    F = qvB sin90

    here we will have

    0.64 \times 10^{-12} = (1.6 \times 10^{-19})(v)(1.9) sin90

    v = 2.1 \times 10^6 m/s

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