A platypus foraging for prey can detect an electric field as small as 0.002 N/C. Part A To give an idea of sensitivity of the platypus’s ele

Question

A platypus foraging for prey can detect an electric field as small as 0.002 N/C. Part A To give an idea of sensitivity of the platypus’s electric sense, how far from a 50nC point charge does the field have this magnitude

in progress 0
Thiên Hương 4 years 2021-08-14T16:32:54+00:00 1 Answers 297 views 0

Answers ( )

    0
    2021-08-14T16:33:55+00:00

    Answer:

    474.34 m

    Explanation:

    From the question,

    E = kq/r²…………….. Equation 1

    Where E = Electric Field, k = coulomb’s constant, q = Charge, r = distance.

    Make r the subject of the equation

    r = √(kq/E)………… Equation 2

    Given: q = 50 nC = 50×10⁻⁹ C, E = 0.002 N/C

    Constant: k = 9×10⁹ Nm²/C².

    Substitute these values into equation 2

    r = √(50×10⁻⁹×9×10⁹/0.002)

    r = √(450/0.002)

    r = √(225000)

    r = 474.34 m

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )