A plane Airport on Tuesday morning for a 755-mile,6- hour trip. For the first part of the tripthe average speed was 105 mphFor the remainder

Question

A plane Airport on Tuesday morning for a 755-mile,6- hour trip. For the first part of the tripthe average speed was 105 mphFor the remainder of the trip the average speed was 130 mph . How long did the plane fly at each speed ?

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Thành Công 4 years 2021-08-20T09:11:34+00:00 1 Answers 12 views 0

Answers ( )

  1. Maris
    0
    2021-08-20T09:13:05+00:00
    Reply

    Answer:

    105 miles / hour for 1 hour

    130 miles / hour for 5 hours

    Step-by-step explanation:

    Part A

    • speed = 105 mph
    • distance = x
    • time = y

    Part B

    • speed = 130 mph
    • distance = 755 miles – x
    • time = 6 hr – y

    plane Part A: x = 105 *y

    Plane Part B: 755 – x = 130*(6 – y)

    Put 105*y into the equation for plane B

    755 – 105*y = 130*(6- y)                            Remove brackets on the the right.

    755 – 105y = 780 – 130y                           Add 130y to both sides

    755 – 105y + 130y = 780                          Combine left

    755 + 25y = 780                                      Subtract 755 from both sides

    25y = 780 – 755                                      

    25y = 25                                                  Divide by 25

    y = 25/25

    y = 1

    The plane travelled 1 hour at 105 mile / hour

    The plane travelled 5 hour at 130 mile / hour

    Check

    1 hour for a distance of 1 hr * 105 mph =  105 mile

    5 hour for a distance of 5 hr*130 mph  = 650 miles

    Total distance =                                          755 miles

    Remark

    This is a very neat problem. I don’t think I’ve ever seen this variation. It is a little long, but it is well worth your time.

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