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a particle of 8 kg is suspended by two light inextensible string that are inclined at the angles find the tension in the string when the pa
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Answer:
T₁ = mg / (sinθ₁ + cosθ₁tanθ₂)
Τ₂ = T₁cosθ₁/cosθ₂
Explanation:
We are not given the angles, but if we assume that they are θ₁ and θ₂ as measured from the horizontal, and associated tensions are T₁ and T₂, we would need two equations to resolve them.
summing horizontal forces to zero
T₁cosθ₁ – Τ₂cosθ₂ = 0
summing vertical forces to zero
T₁sinθ₁ + Τ₂sinθ₂ – mg = 0
Τ₂ = T₁cosθ₁/cosθ₂
T₁sinθ₁ + (T₁cosθ₁/cosθ₂)sinθ₂ = mg
T₁(sinθ₁ + cosθ₁tanθ₂) = mg
T₁ = mg / (sinθ₁ + cosθ₁tanθ₂)