A long, straight wire of radius R carries a steady current I that is uniformly distributed through the cross section of the wire. Calculate

Question

A long, straight wire of radius R carries a steady current I that is uniformly distributed through the cross section of the wire. Calculate the magnetic field a distance r from the center of the wire in regions r ≥ R and r < R.

in progress 0
Sigridomena 4 years 2021-08-04T08:41:09+00:00 1 Answers 15 views 0

Answers ( )

    0
    2021-08-04T08:43:02+00:00

    Answer:

    a

      When r \ge R

          B =  \frac{ \mu_o *  I}{ 2 \pi r }

    b

     When r< R

       B =  [\frac{\mu_o *  I }{ 2 \pi R^2} ]* r

    Explanation:

    From the question we are told that

       The  radius is  R  

       The  current is  I

        The  distance from the center

    Ampere’s law is mathematically represented as

           B[2 \pi r]  =  \mu_o  *  \frac{I r^2  }{R^2 }

          B =  \frac{ \mu_o}{2 \pi }  *  \frac{r}{R^2}

    When r \ge R

    =>     B =  \frac{ \mu_o *  I}{ 2 \pi r }

    But when r< R

       B =  [\frac{\mu_o *  I }{ 2 \pi R^2} ]* r

         

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )