A hungry 173 kg lion running northward at 80.9 km/hr attacks and holds onto a 36.2 kg Thomson’s gazelle running eastward at 63.8 km/hr. Find

Question

A hungry 173 kg lion running northward at 80.9 km/hr attacks and holds onto a 36.2 kg Thomson’s gazelle running eastward at 63.8 km/hr. Find the final speed of the lion–gazelle system immediately after the attack.

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Nguyệt Ánh 4 years 2021-08-25T17:48:40+00:00 1 Answers 9 views 0

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  1. Verity
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    2021-08-25T17:50:14+00:00
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    Answer:

    77.9 km/h

    Explanation:

    We determine the initial momenta of lion and gazelle.

    Lion: 173 × 80.9 = 13995.7

    Gazelle: 36.2 × 63.8 = 2309.56

    Since they are running in the same direction, we add their momenta to get the total initial momentum:

    p_1 = 13995.7+2309.56 = 16305.26

    After the collision, they are together and have a common velocity. Hence, the total final momentum is

    p_2 = (173+36.2)\times v = 209.2v

    By the principle of conservation of momentum, the total initial momentum is equal to the total final momentum, provided there are no external forces.

    209.2v = 16305.26

    v = \dfrac{16305.26}{209.2} = 77.9 \text{ km/h}

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