A hockey stick stores 4.2 J of potential energy when it is bent 3.1 cm. Treating the hockey stick as a spring, what is its spring constant

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A hockey stick stores 4.2 J of potential energy when it is bent 3.1 cm. Treating the hockey stick as a spring, what is its spring constant

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Thiên Di 4 years 2021-08-06T22:02:22+00:00 1 Answers 143 views 0

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  1. nguyetanh
    0
    2021-08-06T22:04:04+00:00
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    Answer:

    Spring constant, k = 8740.89 N/m

    Explanation:

    Given the following data;

    Potential energy = 4.2 J

    Extension, e = 3.1 cm to meters = 3.1/100 = 0.031 m

    To find the spring constant;

    Mathematically, the potential energy stored in a spring is given by the formula;

    P.E = \frac {1}{2}Kx^{2}

    Where;

    P.E is potential energy.

    K is the spring constant.

    x is the extension of the spring.

    Substituting into the equation, we have;

    4.2 = \frac {1}{2}*k*0.031^{2}

    Cross-multiplying, we have;

    8.4 = k*0.000961

    k = \frac {8.4}{0.000961}

    Spring constant, k = 8740.89 N/m

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