A helium balloon has an internal pressure of 2.5 atm when it occupies 4.5 L. If it was compressed until it had a pressure of 3.3 atm, what w

Question

A helium balloon has an internal pressure of 2.5 atm when it occupies 4.5 L. If it was compressed until it had a pressure of 3.3 atm, what would be the final volume? Report your answer with the correct number of significant figures.

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Kim Chi 4 years 2021-08-24T03:33:33+00:00 2 Answers 7 views 0

Answers ( )

  1. minhkhue
    0
    2021-08-24T03:34:35+00:00
    Reply

    Answer: V = 3.4 L

    Explanation: Use Boyle’s Law to find the new volume. P1V1 = P2V2, derive for V2, then the formula will be V2= P1V1 / P2

    V2 = 2.5 atm ( 4.5 L ) / 3.3 atm

    = 3.4 L

  2. Dulcie
    0
    2021-08-24T03:35:11+00:00
    Reply

    Answer:3.40L

    Explanation:

    p1v1=p2v2

    P1=2.5atm

    V1= 4.5L

    P2=3.3atm

    V2=?

    P1V1/P2=V2

    V2=2.5*4.5/3.3

    V2= 11.25/3.3

    V2=3.40L

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