A heat engine operates between 200 K and 100 K. In each cycle it takes 100 J from the hot reservoir, loses 25 J to the cold reservoir, and d

Question

A heat engine operates between 200 K and 100 K. In each cycle it takes 100 J from the hot reservoir, loses 25 J to the cold reservoir, and does 75 J of work. This heat engine violates the second law but not the first law of thermodynamics. Why is this true?

in progress 0
Orla Orla 4 years 2021-08-05T20:10:47+00:00 1 Answers 43 views 0

Answers ( )

  1. trungdung22
    0
    2021-08-05T20:12:14+00:00
    Reply

    Answer:

    It does not violate the first law because the total energy taken is what is used 100J = 25J + 75J

    But violates 2nd lawbecause the engine has a higher energy after doing work than the initial for e.g A cold object in contact with a hot one never gets colder, transferring heat to the hot object and making it hotter confirming the second law

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )