A gas has a solubility of 2.45 g/L at a pressure of 0.750 atm. What pressure wold be required to produce an aqueous solution containing 6.25

Question

A gas has a solubility of 2.45 g/L at a pressure of 0.750 atm. What pressure wold be required to produce an aqueous solution containing 6.25 g/L of this gas at constant temperature

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Euphemia 4 years 2021-08-16T09:52:39+00:00 1 Answers 32 views 0

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  1. hongcuc2
    0
    2021-08-16T09:53:44+00:00
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    Answer:

    1.91 atm

    Explanation:

    Step 1: Calculate Henry’s constant (k)

    A gas has a solubility (C) of 2.45 g/L at a pressure (P) of 0.750 atm. These two variables are related to each other through Henry’s law.

    C = k × P

    K = C/P

    K = (2.45 g/L)/0.750 atm = 3.27 g/L.atm

    Step 2: Calculate the pressure required to produce an aqueous solution containing 6.25 g/L of this gas at constant temperature.

    We have C = 6.25 g/L and k = 3.27 g/L.atm. The required pressure is:

    C = k × P

    P = C/k

    P = (6.25 g/L)/(3.27 g/L.atm) = 1.91 atm

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