A dumbbell-shaped object is composed by two equal masses, m, connected by a rod of negligible mass and length r. If I_1 is the moment of ine

Question

A dumbbell-shaped object is composed by two equal masses, m, connected by a rod of negligible mass and length r. If I_1 is the moment of inertia of this object with respect to an axis passing through the center of the rod and perpendicular to it and l_2 is the moment of inertia with respect to an axis passing through one of the masses, it follows that l_1 = l_2. l_l > l_2. l_2 > l_1

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Huyền Thanh 4 years 2021-08-02T15:57:01+00:00 1 Answers 55 views 0

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  1. thienhuong
    0
    2021-08-02T15:58:50+00:00
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    Answer:I_2>I_1

    Explanation:

    Given

    Shape of the object is dumbbell shaped

    Moment of Inertia w.r.t an axis passing through center and perpendicular to it

    I_1=m(\frac{r}{2})^2+m(\frac{r}{2})^2

    I_1=\frac{mr^2}{2}

    For the axis which passes through one of the masses

    I_2=mr^2

    so I_2>I_1

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