A drop of oil of volume 10 ^-10 m3 spreads out on water to make a circular film radius 10^-1m what is the thickness of the film

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A drop of oil of volume 10 ^-10 m3 spreads out on water to make a circular film radius 10^-1m what is the thickness of the film

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Verity 4 years 2021-08-17T15:42:52+00:00 1 Answers 276 views 0

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  1. Helga
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    2021-08-17T15:44:21+00:00
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    Answer:

    The thickness of the film is = 3.183e-9m

    Explanation:

    It will help us if we understand that the shape of the circular film can be approximated to be a cylinder. The height of this cylinder, or its thickness, in this case, will be very small.

    Since we can approximate the shape of the drop of oil to be a cylinder, after it has spread out on the surface of the water, we can use the cylindrical geometric formulas to find out how thick the film is.

    The volume of a cylinder = \pi r^2 h

    our radius is given as 10^{-1}m = 0.1m

    the volume is 10 ^{-10} m^3=1e-10m^3

    Remember that our task is to find the height of the cylinder. We can do this by making the height the subject of the formula.

    h = \frac{Volume}{\pi r^2} = \\\\\frac{1e-10}{\pi \times 0.1^2} = 3.183e-9m

    Therefore, the thickness of the film is = 3.183e-9m

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