A cylindrical fishing reel has a mass of 0.634 kg and a radius of 3.9 cm. A friction clutch in the reel exerts a restraining torque of 1.52

Question

A cylindrical fishing reel has a mass of 0.634 kg and a radius of 3.9 cm. A friction clutch in the reel exerts a restraining torque of 1.52 N · m if a fish pulls on the line. The fish- erman gets a bite, and the reel begins to spin with an angular acceleration of 54 rad/s 2 . What force does the fish exert on the line?

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Khoii Minh 3 years 2021-08-06T12:14:58+00:00 1 Answers 7 views 0

Answers ( )

  1. niczorrrr
    0
    2021-08-06T12:16:09+00:00
    Reply

    Answer:

    Explanation:

    Given:

    Mass, m = 0.634 kg

    Radius, r = 3.9 cm

    = 0.039 m

    Torque, Trest = 1.52 Nm

    Angular acceleration, α = 54 rad/s^2

    Torque, T = I × α

    Where,

    I = moment of inertia

    Moment of inertia of a solid cylinder, I = 1/2 × m × r^2

    Net torque = summation of all the total torque around the reel

    Tfish = Trest + Treel

    F × r = Trest + I × α

    Inputting values,

    0.039F = 1.52 + ((1/2 × 0.634 × (0.039)^2)) × 54)

    = 1.52 + 0.026

    = 1.546

    Solving for Force, F,

    F = 1.546/0.039

    = 39.64 N

    = 39.6 N.

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