A current of 7.79 A in a solenoid of length 10.6 cm creates a 0.201 T magnetic field at the center of the solenoid. How many turns does this

Question

A current of 7.79 A in a solenoid of length 10.6 cm creates a 0.201 T magnetic field at the center of the solenoid. How many turns does this solenoid contain? turns :

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Linh Đan 4 years 2021-08-31T07:49:15+00:00 1 Answers 9 views 0

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    2021-08-31T07:51:00+00:00

    Answer:

    Therefore,

    2178 number of turns are there in Solenoid.

    Explanation:

    Given:

    Current, I = 7.79 A

    Length of Solenoid,

    L =10.6\ cm=\dfrac{10.6}{100}=0.106\ meter

    magnetic field at the center of the solenoid,

    B = 0.201 Tesla

    To Find:

    N = ? turns

    Solution:

    Magnetic field at the center of the solenoid is given as,

    B=\dfrac{\mu_{0}\times N\times I}{L}

    Where,

    B = Magnetic Field,

    N = Number of turns,

    I = Current,

    L = Length of Solenoid

    \mu_{0}=permeability\ of\ free\ space=4\pi\times 10^{-7}\ H/m

    Substituting the values we get

    N=\dfrac{B\times L}{\mu_{0}\times I}

    N=\dgrac{0.201\times 0.106}{4\pi\times 10^{-7}\times 7.79}=2177.58

    N\approx 2178\ turns

    Therefore,

    2178 number of turns are there in Solenoid.

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