A circular 10-turn coil with a radius of 5.0 cm carries a current of 5 A. It lies in the xy plane in a uniform magnetic field = 0.05 T iˆ+ 0

Question

A circular 10-turn coil with a radius of 5.0 cm carries a current of 5 A. It lies in the xy plane in a uniform magnetic field = 0.05 T iˆ+ 0.3 T kˆ . The coil rotates so that its magnetic moment, μ, is aligned with the magnetic field. The potential energy of the system when the coil’s magnetic moment is aligned with the field is___________.

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Kim Chi 4 years 2021-08-10T09:12:30+00:00 1 Answers 23 views 0

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  1. ThanhThu
    0
    2021-08-10T09:13:48+00:00
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    Answer:

    U = – 0.12J

    Explanation:

    Given N = 10 turns, I = 5A, r = 5×10-²m

    B^ = 0.05 T iˆ+ 0.3 T kˆ

    Magnitude of the magnetic field vector B = √(0.05²+0.3²) = 0.304T

    Area = πr² = π(5×10-²)² = 7.85×10-³m²

    Magnetic moment μ = NIA

    μ = 10×5×7.85×10-³ = 0.3925Am²

    U = -μ•B = –0.3925×0.304 = –0.12J

    The sign is negative because the magnetic moment is aligned with the magnetic field.

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