A child attaches a rubber ball to a string and whirls it around in a circle overhead. If the string is 0.2m long and the ball’s speed is 16

Question

A child attaches a rubber ball to a string and whirls it around in a circle overhead. If the string is 0.2m long and the ball’s speed is 16 m/s, what is the ball’s centripetal acceleration?

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Nick 4 years 2021-08-21T14:54:48+00:00 1 Answers 11 views 0

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  1. vankhanh
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    2021-08-21T14:55:58+00:00
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    Answer:

    The centripetal acceleration, a_c = 1280 m/s^2

    Explanation:

    Centripetal acceleration is given by the formula:

    a_c = \frac{v^2}{r}

    Where the speed of the ball, v = 16 m/s

    Length of the string, r = 0.2 m

    Substituting these parameters into the centripetal equation above:

    a_c = \frac{16^2}{0.2}\\a_c = \frac{256}{0.2}\\a_c = 1280 m/s^2

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