A car traveling at 26.8m/s hits the brakes to slow down before turning into a neighborhood. Determine how fast it is going after slowing dow

Question

A car traveling at 26.8m/s hits the brakes to slow down before turning into a neighborhood. Determine how fast it is going after slowing down at a rate of -8.2m/s2 for 14.3seconds.

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Thiên Thanh 4 years 2021-07-28T21:56:17+00:00 1 Answers 7 views 0

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  1. Amity
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    2021-07-28T21:57:50+00:00
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    Answer:

    The speed of the car after the break was applied is  90.46 m/s

    Explanation:

    Given;

    initial velocity of the car, u = 26.8 m/s

    accelertation of the car, a = -8.2 m/s²

    time of motion, t = 14.3 s

    final velocity, v = ?

    Apply the following kinematic equation;

    v = u + at

    v = 26.8 + (-8.2 x 14.3)

    v = 26.8 –  117.26

    v = -90.46 m/s

    magnitude of the final velocity = 90.46 m/s

    Therefore, the speed of the car after the break was applied is  90.46 m/s

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )