A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J. At this time, the rocket runs out of

Question

A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.

At this time, the rocket runs out of fuel and turns off, and the car deploys a parachute to slow down, and the parachute performs 36,733 J of work on the car.

What is the final speed of the car after this work is performed?

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King 4 years 2021-08-07T22:16:58+00:00 1 Answers 11 views 0

Answers ( )

  1. Helga
    0
    2021-08-07T22:18:07+00:00
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    Answer:

    9.43 m/s

    Explanation:

    First of all, we calculate the final kinetic energy of the car.

    According to the work-energy theorem, the work done on the car is equal to its change in kinetic energy:

    W=K_f - K_i

    where

    W = -36.733 J is the work done on the car (negative because the car is slowing down, so the work is done in the direction opposite to the motion of the car)

    K_f is the final kinetic energy

    K_i = 66,120 J is the initial kinetic energy

    Solving,

    K_f = K_i + W = 66,120 + (-36,733)=29,387 J

    Now we can find the final speed of the car by using the formula for kinetic energy

    K_f = \frac{1}{2}mv^2

    where

    m = 661 kg is the mass of the car

    v is its final speed

    Solving for v, we find

    v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.43 m/s

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