A ball is thrown upward. At a height of 10 meters above the ground, the ball has a potential energy of 50 joules (with the potential energy

Question

A ball is thrown upward. At a height of 10 meters above the ground, the ball has a potential energy of 50 joules (with the potential energy equal to zero at ground level) and is moving upward with a kinetic energy of 50 joules. Air friction is negligible. The maximum height reached by the ball is most nearly

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Nick 4 years 2021-08-21T14:52:31+00:00 1 Answers 69 views 0

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  1. thienthi
    0
    2021-08-21T14:54:17+00:00
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    Answer: 20m

    Explanation:

    We will solve this question by applying the law of conservation of energy which states that the sum of potential energy and kinetic energy is always the same.

    The PE is 0 at surface and maximum at top while the KE is maximum at surface and 0 at top.

    From the question,

    PE = mgh = 50 J -(1)

    mg* 10 = 50

    mg = 50/10

    mg = 5

    The total energy at that point = PE + KE = 50 + 50 = 100 J

    Therefore, at topmost point, the PE will be 100 J

    mgH = 100J , H is the needed height

    Using the value of mg obtained above, we have

    H= 100/5

    H = 20 m

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