A 62.2 kg ice skater moving to the right with a velocity of 2.66 m/s throws a 0.145 kg snowball to the right with a velocity of 39.3 m/s rel

Question

A 62.2 kg ice skater moving to the right with a velocity of 2.66 m/s throws a 0.145 kg snowball to the right with a velocity of 39.3 m/s relative to the ground. What is the velocity of the ice skater after throwing the snowball? Disregard the friction between the skates and the ice.

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Thu Thảo 5 years 2021-08-22T20:36:53+00:00 1 Answers 24 views 0

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  1. hongcuc2
    0
    2021-08-22T20:38:08+00:00
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    Answer:

    Velocity of skater after throwing the snowball is 2.57 m/s

    Explanation:

    Given :

    Mass of skater, M = 62.2 kg

    Mass of snowball, m = 0.145 kg

    Velocity of snowball relative to ground, v = 39.3 m/s

    Consider v₁ be the velocity of skater after throwing the snowball.

    According to the problem, initially the velocity of skater and snowball is same. So,

    Velocity of skater before throwing snowball, u = 2.66 m/s

    Applying conservation of momentum,

    Momentum before throwing snowball = Momentum after throwing snowball

    (M + m) u = Mv₁ + mv

    v_{1}=\frac{(M+m)u-mv}{M}

    Substitute the suitable values in the above equation.

    v_{1}=\frac{(62.2+0.145)2.66-0.145\times39.3}{62.2}

    v₁ = 2.57 m/s

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