A 3.6-volt battery is used to operate a cell phone for an hour. If the cell phone draws a current of 0.018 Amperes during that time, what is

Question

A 3.6-volt battery is used to operate a cell phone for an hour. If the cell phone draws a current of 0.018 Amperes during that time, what is the energy lost by the battery?

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Thành Đạt 5 years 2021-07-29T18:02:07+00:00 2 Answers 69 views 0

Answers ( )

  1. ngocdiep
    0
    2021-07-29T18:03:37+00:00
    Reply

    Answer:

    the energy lost by the battery is 233.28Joules

    Explanation:

    Energy = Power × Time

    We know that the power is given by :

    P=V \times I

    Power = Current (I)×potential difference (V)

    Energy lost = current × potential difference × time

    E = I \times V \times t

    Given that

    current, I = 0.018Amperes,

    Potential diff ,V = 3.6Volts

    timr, t = 1hour = 1×60×60 = 3600seconds

    Energy lost. = 0.018×3.6×3600

    = 233.28Joules

    Hence, the energy lost by the battery is 233.28Joules

  2. ngockhue
    0
    2021-07-29T18:03:52+00:00
    Reply

    Answer:

    233.28Joules

    Explanation:

    Energy lost by the battery is expressed as

    Energy = Power × Time

    Since Power user up = Current (I)×potential difference (V)

    Energy lost = current × potential difference × time

    Energy used up = IVt

    Given the following parameters

    I = 0.018Amperes, V = 3.6Volts t = 1hour = 1×60×60 = 3600seconds

    Energy lost. = 0.018×3.6×3600

    Energy lost by the battery = 233.28Joules

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