a 2kg block of wood starts at rest and slides down a ramp. Its initail height is 12m. if the final velocity of the block is 13m/s, determine

Question

a 2kg block of wood starts at rest and slides down a ramp. Its initail height is 12m. if the final velocity of the block is 13m/s, determine the energy of this system that has been turned into heat

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Sapo 3 years 2021-07-16T02:08:19+00:00 1 Answers 14 views 0

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  1. King
    0
    2021-07-16T02:09:42+00:00
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    Answer:

    E = 66.44 J

    Explanation:

    From the law of conservation of energy:

    Total Mechanical Energy at Start = Total Mechanical Energy at the End

    Potential Energy at Start = Kinetic Energy at End + Energy Lost

    mgh = \frac{1}{2} mv^2 + E\\\\E = mgh - \frac{1}{2} mv^2\\\\

    where,

    E = Energy turned into heat = ?

    m = mass of block = 2 kg

    g = acceleration due to gravity = 9.81 m/s²

    h = height = 12 m

    v = final speed = 13 m/s

    Therefore,

    E = (2\ kg)(9.81\ m/s^2)(12\ m)-\frac{1}{2} (2\ kg)(13\ m/s)^2\\\\E = 235.44\ J - 169\ J\\

    E = 66.44 J

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