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A 28-g rifle bullet traveling 190 m/s embeds itself in a 3.1-kg pendulum hanging swing upward l an arc. Determine the vertical and horizonta
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Answers ( )
Answer:
V = 0.15m
H = 0.85m
Explanation:
We will be using the conservation of momentum to solve the problem.
m(i).v(i) = m(f).v(f) where
0.028 * 190 = 3.1 * v(f)
v(f) = 5.32/3.1
v(f) = 1.72 m/s
next, we use the conservation of energy to find the vertical displacement.
½mv² = mgh
½v² = gh, making h the subject of formula, we have
h = v²/2g
h = 1.72²/ 2 * 9.81
h = 2.9584 / 19.62
h = 0.15 m
The height, h is the vertical displacement.
Next, we find the angle of the pendulum at the top of the swing.
Φ = cos^-1 [(2.5 – 0.15)/2.5] *the height at which the pendulum is hanging is not given, so I assumed it to be 2.5m, yo can substitute that for whatever it is
Φ = cos^-1(2.35/2.5)
Φ = cos^-1 (0.94)
Φ = 19.95°
This gotten angle is used to find the horizontal displacement
x = 2.5 sinΦ
x = 2.5 sin 19.95
x = 2.5 * 0.34
x = 0.85 m