A 16.2-g bullet with an initial speed of 850 m/s embeds itself in a 40.0-kg block, which is attached to a horizontal spring with a force con

Question

A 16.2-g bullet with an initial speed of 850 m/s embeds itself in a 40.0-kg block, which is attached to a horizontal spring with a force constant of 1000 N/m. What is the maximum compression of the spring

in progress 0
Thiên Thanh 4 years 2021-08-11T05:44:14+00:00 1 Answers 98 views 0

Answers ( )

  1. thucuc
    0
    2021-08-11T05:45:35+00:00
    Reply

    Answer:

    4.74 mm

    Explanation:

    Not very much. Even less with any friction.

    Conservation of momentum during the collision

    0.0162(850) + 40.0(0) = 40.0162v

    v = 0.344 m/s

    The kinetic energy of the block/bullet mass will convert to spring potential energy.

    ½kx² = ½mv²

    x = √(mv²/k)

    x = √(40.0162(0.344²) / 1000)

    x = 0.0047384… m

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )